-- The number that (x2-y2) represents depends on the values of 'x' and 'y', which
you haven't seen fit to include.
-- When (x2-y2) is factored, it can be represented as [ (x+y) times (x-y) ], which is
often easier to evaluate, or integrate, or differentiate, than the original expression is.
But you still need to know the values of 'x' and 'y'.
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.
By factoring I get x-3 divided by x+3
(x2 - y2)/(x - y) = (x + y)(x - y)/(x - y) = x + y
xcubed-1 Answer::(X-1)(Xsquared+X+1) when you factor xcubed minus a number its the same thing as x cubed minus y cubed and x cubed minus y cubed factors to:: (x-y)(xsquared+xy+y squared) the first factor, (x-y), is the cubed root of the first and the cubed root of the second, so in the answer i have (x-1), which is x cubed minus one cubed :) the second factor, (xsquared+xy+ysquared), you take the first number squared, Xsquared, then the first and second one multiplied together, XY, and then the second number squared, Ysquared, so in the answer i have (xsquared+x+1), which is x squared, then x times 1 which is just x, and positive 1, which is negative 1 squared :) x^3 - 1
xsquared minus x minus 72
2
it is (x-y)(x-y) :)
The factoring is as follows: x2 - y2 = (x + y) * (x - y)
You have to put your heart into it!
x^2 - y^2 - 4 is in its simplest form.
There are no rational factors.
(x, y) = (-3, -3) or (3, 3)
(x - y)(x + y)
(x - y)2 = x2 - 2xy + y2
(x^2 - y^2) / (x - y) Apply the difference of squares formula: (x + y)(x - y) / (x - y) Assuming x is not equal to y, we can cancel terms leaving x + y When x = y, the denominator becomes 0, and the equation gives no information.
4
The solutions are: x = 4, y = 2 and x = -4, y = -2