Well, if that was a - 13X we could factor by inspection, but now the quadratic formula is needed. By inspection the discriminant yields two real roots.
X^2 + 13X + 36 = 0
X = - b (+/-) sqrt(b^2-4ac)/2a
a = 1
b = 13
c = 36
X = - 13 (+/-) sqrt[b^2 - 4(1)(36)]/2(1)
X = - 13 (+/-) sqrt(169 - 144)/2
X = - 13 (+/-) sqrt(25)/2
X = [- 13 (+/-) 5]/2
X = - 4
------------
X = - 9
-----------
It's a quadratic expression: x²+13x+12 If, for example, x²+13x+12 = 0 then there are 2 roots, x=-1 and x=-12
Since 7x + 13x +2x + 8 is an expression (there is no equal sign), there is no answer as to what x equals. However, this expression can be simplified to 22x + 8.
2x - 13x + 42 = x +ax + b a + b = 2(x - 6.5x + 21) = 34 = a + b
2x2 + 13x - 7 = zero(2x - 1 )( x + 7 ) = zero2x - 1 = zerox = 1/2x + 7 = zerox = -7
x2 + 13x + 36 = 0 so (x+4)(x+9) = 0 so that x = -4 or x = -9
(13x^2 - 4y)(2x^2 - 5y)
It is x^2 -13x +12 = (x-1)(x-12) when factored
42 + x2 = 13x ∴ x2 - 13x + 42 = 0 ∴ (x - 6)(x - 7) = 0 ∴ x ∈ {6, 7}
It is (2x-5)(x-4) when factored
it equals 13X.
x^2 - 13x + 36 = 0 Factor: (X-9)(X-4) = 0 X = 9 X = 4
13x
x + 13x + 10x = 50 - 6
2x2+13x+15 = (2x+3)(x+5)
Multiply all terms by 10 it then becomes 10x2+13x+4 = (5x+4)(2x+1) when factored.
5x2 + 3x + 8x2 = 13x2 + 3x = x(13x + 3)
-6 = 3 x -2 13 = 5 x 3 - 2 → 5x² + 13x - 6 = (5x - 2)(x + 3)