Solving the system of equations:
y = 3x +1
y = 2x -1
(assuming that is what the question intend. Please be more clear.)
subtracting the second equation from the first to eliminate y, we get:
0 = x + 2 => x=-2
plugging thus back in to the second equation:
y = 2(-2) - 1 = -5
Thus we have x = -2, y = -5
If 3x + 5x = -8, what is x + 1? 3x + 5x = -8 8x = -8 x = -1 x + 1 = -1 + 1 = 0
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
(3x + 1) = -3 (x + 2x -1) (3x + 1) = -3 (3x - 1) 3x + 1 = -9x + 3 12x = 2 6x = 1 x = 0.16666666666666666666666666666666666666666666666666666666666666666666
X = -2(13 + y) / 3x = 5y / 4 - 1
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
(2, -1)
y = 3X - 1
y = 3x + 1
If: 3x+5 = 4x+1 Then: x = 4
(1, 1)
x + 2 = 3x-1 -2x = -3x = 1,5
It is called the commutative property, a + b = b + a
1
0 because X= -1
2x+5=3x+1 -x=-4 x=4
3x(2x + 1)
If 3x + 5x = -8, what is x + 1? 3x + 5x = -8 8x = -8 x = -1 x + 1 = -1 + 1 = 0