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Solving the system of equations:
y = 3x +1
y = 2x -1
(assuming that is what the question intend. Please be more clear.)
subtracting the second equation from the first to eliminate y, we get:
0 = x + 2 => x=-2
plugging thus back in to the second equation:
y = 2(-2) - 1 = -5
Thus we have x = -2, y = -5
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3x plus 5x equals -8 then x plus 1 equals?
If 3x + 5x = -8, what is x + 1? 3x + 5x = -8 8x = -8 x = -1 x + 1 = -1 + 1 = 0
4x equals 3x plus 1 what is x?
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
Solve 3x plus 1 divided by x plus 2x minus 1 divided by 3 equals -3?
(3x + 1) = -3 (x + 2x -1) (3x + 1) = -3 (3x - 1) 3x + 1 = -9x + 3 12x = 2 6x = 1 x = 0.16666666666666666666666666666666666666666666666666666666666666666666
What is the answer to 3X plus 2Y equals -26 and 4X minus 5Y equals -4?
X = -2(13 + y) / 3x = 5y / 4 - 1
3x plus 2 plus 2x equals 7?
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
