Yes, if the number is less than '1'.Just the opposite, if the number is greater than '1'.
x can be any number greater than 16 and less than 81.
The answer is 11 !
You cannot prove it because it is not necessarily true. A = 16 < B = 25 But one square root of A = +4 is not less than one square root of B = -5.
No. The square roots of numbers between 0 and 1 (not including 0) are greater than or equal to (in the case of 1) the number. The square root of 0.49 is 0.7 for example.
It is if the number is more than ' 1 '. If the number is less than ' 1 ', then it's smaller than its own square root.
No, not always since: if a number is more than 1, then its square root is smaller than the number. if a number is less than 1, then its square root is bigger than the number.
when the number is greater than 1
Yes, if the number is less than 1
The square root of 2.
Yes, if the number is less than '1'.Just the opposite, if the number is greater than '1'.
a square number is a number that you multiply the same number like:8.8 = 64 get it
139, the square root of 19321 is less than 140.
15
9/5
The number is 3 less than the square root of 16 ie 3 less than 4, so it's 1.
No there is not. If you are looking for prime factors of a number and you get to the square root of that number you can stop. Yes, there is. If an integer is not itself a prime, then one of its factors will be less or equal to its square root and the "co-factor" will be greater than or equal to the square root. But both cannot be greater than the square root so, when searching for factors, you can stop when you reach the square root.