Since 8 is divisible by 4, but 4 is not divisible by 8, we can rule out the requirement of being divisible by 4 because it is superfluous. So, all of the numbers that are divisible by 8... because the set of integer numbers is infinite, there is no point in listing them since it will be an incomplete list (this is proven by the fact that no matter what integer you have, another one can be made by simply adding one). So the set of integer numbers divisible by 8 is also infinte (because you can go as high as you like, and yet another can be made simply by adding 8). So it is pointless to try and list all of them because there would be no end to the list. However, here are some of the first few: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160...
The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.
To find the numbers between 1 and 100 inclusive that are divisible by either 9 or 4, we first determine how many numbers are divisible by 9 and how many are divisible by 4. There are 11 numbers divisible by 9 (9, 18, 27, ..., 99) and 25 numbers divisible by 4 (4, 8, 12, ..., 100). However, we must be careful not to double-count numbers divisible by both 9 and 4 (36, 72). Therefore, the total number of numbers divisible by 9 or 4 between 1 and 100 inclusive is 11 + 25 - 2 = 34.
To find numbers between 30 and 40 that are divisible by both 4 and 9, we need to find the least common multiple of 4 and 9, which is 36. The numbers between 30 and 40 that are divisible by 4 and 9 are 36.
No. If the last two numbers are not divisible by 4, then the number is not divisible by 4.
Odd numbers are not divisible by even numbers.
1, 2, 4, 5, and 10
Any multiples of 4 including itself is divisible by 4
0,12,24,36,48,60,72,84, and 96 are the numbers between 0 and 100 that are divisible by both 3 and 4.
Yes.
12.
1, 2 and 3
Yes.Two tests for divisibility by 4:If the last two digits are divisible by 4 the whole number is divisible by 4. (In both cases, the last two digits are 52 and 52 is divisible by 4 (52 = 4 x 13), so the original numbers are both divisible by 4.)Add the units digit to twice the tens digit; if this sum is divisible by 4, so is the original number. (In both cases: 2 + 2x5 = 12 which is divisible by 4 (12 = 4 x 3), so the original numbers are both divisible by 4.)
The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.
Oh, dude, numbers that are divisible by both 4 and 5 are multiples of their least common multiple, which is 20. So, like, 20, 40, 60, and so on are all numbers that fit the bill. But hey, who's counting, right?
Oh, dude, you're looking for numbers that are divisible by both 4 and 7? Well, when those two get together and have a party, their love child numbers are like 28, 56, 84, and so on. It's like a cool math club where only the multiples of 4 and 7 are allowed to hang out.
40 is nearest to 39 and is exactly by divisible 4
To find the numbers between 1 and 100 inclusive that are divisible by either 9 or 4, we first determine how many numbers are divisible by 9 and how many are divisible by 4. There are 11 numbers divisible by 9 (9, 18, 27, ..., 99) and 25 numbers divisible by 4 (4, 8, 12, ..., 100). However, we must be careful not to double-count numbers divisible by both 9 and 4 (36, 72). Therefore, the total number of numbers divisible by 9 or 4 between 1 and 100 inclusive is 11 + 25 - 2 = 34.