102, 105, 108, 111 and just keep adding three until you get to 399.
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There are 22 numbers between 400 and 600 that are divisible by nine.
There are 300 whole numbers between 100 and 400, inclusive. To find this, you subtract 100 from 400 to get the total range of numbers (400 - 100 = 300). Then, since we're considering whole numbers, we add 1 to include the endpoints (400 and 100). Therefore, there are 300 whole numbers between 100 and 400.
400 / 7 = 57, so there are 57 multiples of 7 under 400.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
300.