Assuming you have to use all of the numbers: (9 - 4 - 1) x 6 = 24
1 and 18 2 and 9 3 and 6
The range of these numbers is 9 - 1 = 8.
abs(4 - 9) * 6 - 6 or, equivalently, (9 - 4)*6 - 6
1+2+3+4+5+6+7+8+9 = 45
9 +16 -1 = 24
Assuming you have to use all of the numbers: (9 - 4 - 1) x 6 = 24
(9/9)*1^6
Turn the paper upside down. When you flip the page you will notice that the 6 becomes a 9. Now make 12 by circling the numbers 1, 9, 1, 1.
1 = 1 2 = 2 3 = 2+1 4 = 6-2 5 = 6-1 6 = 6 7 = 6+1 8 = 6+2 9 = 9 10 = 9+1 11 = 9+2 12 = 9+2+1 13 = 2*6+1 14 = 9+6-1 15 = 9+6 16 = 9+6+1 17 = 9+6+2 18 = 9+6+2+1 19 = 9*2+1 20 = (9+1)*2
1234 - 5 - 6 + 789
0 + 9 = 9 1 + 8 = 9 2 + 7 = 9 3 + 6 = 9 You can also, of course, use fractions and negative numbers.
(3/9*1)+4+5+7-2-6-8
9 + 28 +37 + 6 + 15 + 4 = 99
1 + (2+3+8+9) - (4+5+6+7) = 1
9 x 5 = 45 - 6 = 39 - 9 = 30 - 1 = 29.I know this and I'm 8!
(3-1) x (2+8)(9-6) Essentially, the above sum is 2x103