If it's just factors, then any number have an even amount of factors.
Let a be any number, a = 1 a
so a have two factors, 1 and a. Two is even.
But if the question is what number have an even amount of PRIME factors, then it is different. Because if a is not prime, the might exist another two numbers b and c != 1 such that a = b c. and also, b is not prime, b = d e
So a = bc = de c = c d e So a have three prime factors (1 is not prime for some reason)
Then this question is less trivial:
6 have only prime factor 2 and 3, 10 only have prime factor 2 and 5, they are even.
but 9 only have prime factor 3, so it's not an even amount, so 9 is not.
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Both odd and even numbers may have odd numbers as factors.
No. the factors may be both even but only one of them needs to be.
There are countless numbers with more than 6 factors. 540, for example has 24 factors, and some numbers have even more.
Even numbers.
2, 4, 6, 12