If it's just factors, then any number have an even amount of factors.
Let a be any number, a = 1 a
so a have two factors, 1 and a. Two is even.
But if the question is what number have an even amount of PRIME factors, then it is different. Because if a is not prime, the might exist another two numbers b and c != 1 such that a = b c. and also, b is not prime, b = d e
So a = bc = de c = c d e So a have three prime factors (1 is not prime for some reason)
Then this question is less trivial:
6 have only prime factor 2 and 3, 10 only have prime factor 2 and 5, they are even.
but 9 only have prime factor 3, so it's not an even amount, so 9 is not.
Both odd and even numbers may have odd numbers as factors.
No. the factors may be both even but only one of them needs to be.
There are countless numbers with more than 6 factors. 540, for example has 24 factors, and some numbers have even more.
Even numbers.
2, 4, 6, 12
All compound numbers that are not perfect squares.
Some even numbers have more factors than some odd numbers and some odd numbers have more factors than some even numbers. As a group, even numbers have more factors than odd numbers.
Some even numbers have more factors than some odd numbers and some odd numbers have more factors than some even numbers. As a group, even numbers have more factors than odd numbers.
All nonzero numbers have factors. Some factors are even numbers, some factors are odd numbers.
Square numbers.
do you mean " what does all even numbers have as factors?"? then the number two.
even factors are numbers you divied and there is a remander
even numbers
1 and 2 are factors of all even numbers.
it is the integers of even numbers which divide all the even numbers
1 and 2 are factors of all even numbers.
They are square numbers.