figure out what they're trying to ask you to imagine. I'm not exactly sure how to look at the question though... should i imagine the numbers in half, imagine what numbers would look symmetrical and next to each other, both, or neither?
sorry if this is just a waste of space, but all i know is that you have to see where to begin before trying to figure out what 9 would look like if beheaded (which would either be a 1 or a 7... i know they're not even but they could be in the tens or hundreds place).
also say the numbers aloud and see if this is a verbal riddle/joke. like 62 (sixty two... sick tea too) or something like that.
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
odd * odd = odd answer even * even = even answer odd * even = even answer
Odd
37
If the last number is odd or even then the whole number is odd or even, in this case the last number is 3 which is an odd number, therefore the whole number is odd.
They have only one thing in common. By adding 1 to either an even number or an odd number makes them opposite. (even becomes odd and odd becomes even).
eleven - el = even
7.
eleven
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Because an even number times an odd number is an even number. Any even number multiplied by an odd number produces another even number. So the odd number that you multiplied by becomes a factor of the bigger even number. 3 x 2 = 6 6 is an even number, but one of its factors is 3 .
odd * odd = odd answer even * even = even answer odd * even = even answer
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
"IT IS ALWAYS A ODD"
No. Sum of odd + odd = even Sum of odd + even = odd Sum of even + even = even
Odd
37