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If it has those roots, the simplest one will have (x+2),(x-2),(x+3). So multiply those three together. =(x^2-4)(x+3)=x^3+3x^2-4x-12.

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Q: What polynomial equation has the roots -2 2 -3?
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In a cubic polynomial 2xxx-5xx-14x 8 find the sum of the zeros?

2x^3 - 5x^2 - 14x + 8 Let P(x) represents the cubic polynomial. We can find the sum of x-values which make P(x) = 0, (the sum of the roots of the equation) P(x) = 2x^3 - 5x^2 - 14x + 8 P(x) = 0 2x^3 - 5x^2 - 14x + 8 = 0 Since the degree of this polynomial is odd, then the sum of the roots is -[a(n - 1)/an], where a(n-1) is -5 and an is 2. So we have, -[a(n - 1)/an] = -(-5/2) = 5/2 Thus the sum of the roots is 5/2.


How many roots does a quadratic equation in one variable have?

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