2x^3 - 5x^2 - 14x + 8
Let P(x) represents the cubic polynomial. We can find the sum of x-values which make P(x) = 0, (the sum of the roots of the equation)
P(x) = 2x^3 - 5x^2 - 14x + 8
P(x) = 0
2x^3 - 5x^2 - 14x + 8 = 0
Since the degree of this polynomial is odd, then the sum of the roots is -[a(n - 1)/an], where a(n-1) is -5 and an is 2. So we have,
-[a(n - 1)/an] = -(-5/2) = 5/2
Thus the sum of the roots is 5/2.
when the equation is equal to zero. . .:)
Multiply x3 - 2x2 - 13x - 10
take out zeros
a
(b+8)(b+8)
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
when the equation is equal to zero. . .:)
by synthetic division and quadratic equation
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
If there is one variable. Then put each variable equal to zero and then solve for the other variable.
Multiply x3 - 2x2 - 13x - 10
In general, there is no simple method.
If you have the zeros of a polynomial, it is easy, almost trivial, to find an expression with those zeros. I am not sure I understood the question correctly, but let's assume you have the zero 2 with multiplicity 2, and other zeros at 3 and 5. Just write the expression: (x-2)(x-2)(x-3)(x-5). (Example with a negative zero: if there is a zero at "-5", the factor becomes (x- -5) = (x + 5).) You can multiply this out to get the polynomial if you like. For example, if you multiply every term in the first factor with every term in the second factor, you get x2 -2x -2x + 4 = x2 -4x + 4. Next, multiply each term of this polynomial with each term of the next factor, etc.
The remainder theorem states that if you divide a polynomial function by one of it's linier factors it's degree will be decreased by one. This theorem is often used to find the imaginary zeros of polynomial functions by reducing them to quadratics at which point they can be solved by using the quadratic formula.
7w2 -17w+16 is a polynomial that cannot be factored. We call this a prime polynomial.There are also no like terms to combine. So nothing much more can be done with this polynomial. If you wanted to find the roots or the zeros, you could use the quadratic formula.
13 is not a polynomial.
Find values of the variable for which the value of the polynomial is zero.