x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
There is no number that can multiplied by 0 to get 1. The equation 0x = 1 has no solution bcause 0x = 0 whatever number x may be. You might think that 1/0 times 0 would equal 1 but 1/0 is not a number.
x^2 + 12x + 36 = 0(x + 6)(x + 6) = 0(x + 6)^2 = 0√(x + 6)^2 = ± √0x + 6 = 0x + 6 - 6 = 0 - 6x = 6
identity property of multiplication
x2 = 8xx2- 8x = 0x(x - 8) = 0x = 0 ;x - 8 = 0x = 8
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
This is always true! According to the Additive Inverse Axiom -X+X always equals 0 which is equivalent to 0X.
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
x + 4x = 05x = 0x = 0/5x = 0
x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5
y = 2x - x2y = 0Since both quantities on the right side are equal to 'y', they're equal to each other.2x - x2 = 0x (2 - x) = 0x = 0and2 - x = 0x = 2The two points of intersection are (0, 0) and (2, 0) .
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
None.Whatever number you substitute for 'x', 0x will always be 0,and the equation will always become [ 0 = 4 ].No value of 'x' can make [ 0 = 4 ]. There is no solution.
x+(-2.5)+6.8=0x+(-2.5+6.8)=0x+(4.3)=0x+4.3=0Subtract 4.3 from both sides and you get:x= -4.3
x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5