It is n + 6.
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n = number n + 6 ======
6 + n = 21
6(n + y)
If n is the first number, n + n + 1 + n + 2 + n + 3 will be the sum, which is 4n + 6. 4n is always even, and 6 is even. Therefore, the sum of four consecutive numbers is always even.
(6+n) n= a number