What two numbers have a difference of 7 and a sum of 29?

Answer 1

X - Y = 7 eqn 1
X + Y = 29 eqn 2

Taking eqn 1 we can isolate for X
X-Y = 7
add Y to both sides
X = 7 + Y

Substituting this into eqn 2 we get

X + Y = 29
(7 + Y) + Y = 29
7+ 2Y = 29
subtract 7 from both sides
2Y = 22
divide both sides by 2
Y = 11
Substituting this into eqn 1 we get
X - 11 = 7
add 11 to both sides
X = 18

So X = 18 and Y = 11

Answer 2

Let's denote the two numbers as x and y. We know that x - y = 7 and x + y = 29. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations together, we get 2x = 36, so x = 18. Substituting x back into the second equation, we find y = 11. Therefore, the two numbers are 18 and 11.