6
Let's say Un=aqn and Sn=a+aq+aq2+aq3+aq4+aq5+...+aqn Sn = a (1+q+q2+q3+q4+q5+...+qn) A=(Sn/a) - q (Sn/a) = (1+q+q2+q3+q4+q5+...+qn) - q(1+q+q2+q3+q4+q5+...+qn) A=1+q+q2+q3+q4+q5+...+qn-q-q2-q3-....-qn-qn+1=1-qn+1 So A = 1-qn+1 = Sn/a (1-q) So Sn = a (1-qn+1)/(1-q)
The SN of 14.05 billion is: 14,050,000,000
i got the same question for homework in functions. tn=a+(n-1)d -50=-1+(n-1)-1 -50=-1-1n+1 -50=-1n therefore n=50 plug that into your sum equation...for convenience i used Sn=50/2 (-1-50) Sn=25 (-51) Sn= -1275 hope this helps!
make an A.P i.e:- 2,4,6,8..................200 therefore a=2 d=2 an=200 a+(n-1)d=200 2+(n-1)(2)=200 (n-1)(2)=198 N=100 Sn=100/2+[2+200] sn=50[202] sn=10100 . . . . . . . therefore sum of first even natural numbers is 10100
Sn = 3n2 + 2n - 8
The SN reaction is a substitution reaction. An example of the SN reaction is Br. H3CH2C.
The oxidation number of Sn changes from +4 in SnCl4 to +2 in SnCl2, resulting in a decrease of 2.
The balanced chemical equation shows a 1:1 ratio between Sn and SnF2. Since Sn is limiting in this reaction, the maximum amount of SnF2 that can be produced will be equal to the amount of Sn used, which is 0.480 moles. Therefore, 0.480 moles of SnF2 can be produced.
To find the grams of Sn formed, we first need to calculate the number of moles of SnO2 in 12.5 grams. Then, we use the stoichiometry of the reaction to relate the number of moles of SnO2 to the number of moles of Sn. Finally, we convert the moles of Sn to grams using the molar mass of Sn.
The half reaction you mentioned is the oxidation of Sn(II) to Sn(IV) with the loss of two electrons. This reaction represents the conversion of tin(II) ions (Sn2+) to tin(IV) ions (Sn4+).
When nitric acid reacts with tin, the tin is oxidized to form tin(II) nitrate and nitrogen dioxide gas is also produced as a byproduct. The chemical equation for this reaction is: 4HNO3 + Sn → Sn(NO3)2 + 2NO2 + 2H2O
The balanced equation for the reaction is: 4HNO3 + Sn -> SnO2 + 4HNO2 + 2H2O
The reaction between HCl (hydrochloric acid) and Sn (tin) forms SnCl2 (tin(II) chloride) and hydrogen gas (H2). The balanced chemical equation for this reaction is: Sn + 2HCl → SnCl2 + H2.
fusion
The product of Sn with HCl is tin chloride (SnCl2) and hydrogen gas (H2). The reaction can be represented as Sn + 2HCl -> SnCl2 + H2.
When tin reacts with sulfuric acid, it forms tin(II) sulfate and hydrogen gas is released. The chemical equation for the reaction is: Sn + H2SO4 -> SnSO4 + H2
No because zinc is more reactive than tin so it dilutes it