You have the 3rd term and you want to go out four more so multiply by 5 this many times:
125*5^4 = 78125
To find the seventh term in the sequence -6, -11, -16, -21, -26, we first identify the pattern: each term decreases by 5. Therefore, the next term would be -26 - 5 = -31. Continuing this pattern, the seventh term would be -31 - 5 = -36.
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
In a sequence, the ratio of the third term to the second term is the one successive from the ratio of the second to the first. The successive ratios are : u2/u1, u3/u2, u4/u3 and so on. In a geometric sequence, these would all be the same.
No, it would have to be ten fourteenths to equal five sevenths or one seventh equals two fourteenths.
Geometric Sequences work like this. You start out with some variable x. Your multiplication distance between terms is r. Your second term would come out to x*r, your third x*r*r, and so on. If there are n terms in the sequence, your final term will be x*r^(n-1).
Of sorts. 1 3 6 10 15 would have a geometric representation, but would not fit the definition of a "geometric sequence". One example of a geometric representation of the sequence would be the number of total bowling pins as you add each row. The first row as 1 pin, the second has 2, then 3,4,5. 1 = 1 + 2 = 3 + 3 = 6 + 4 = 10 + 5 = 15
No, it is geometric, since each term is 1.025 times the previous. An example of an arithmetic sequence would be 10, 10.25, 10.50, 10.75, 11.
To find the seventh term in the sequence -6, -11, -16, -21, -26, we first identify the pattern: each term decreases by 5. Therefore, the next term would be -26 - 5 = -31. Continuing this pattern, the seventh term would be -31 - 5 = -36.
The 99th term would be a times r to the 98th power ,where a is the first term and r is the common ratio of the terms.
In a sequence, the ratio of the third term to the second term is the one successive from the ratio of the second to the first. The successive ratios are : u2/u1, u3/u2, u4/u3 and so on. In a geometric sequence, these would all be the same.
The sequence, -7, -21, 63 could be generated by Un = 49n2 - 161n + 105 so when n = 9 the term would be 2625.
You would be the seventh child of your father who would have to be the seventh child of his family.
The geometric mean of two numbers is the square root of their product. In this case, the geometric mean of 5 and 25 would be the square root of (5 * 25) which equals the square root of 125. Simplifying further, the square root of 125 is approximately 11.18. Therefore, the geometric mean of 5 and 25 is approximately 11.18.
Each number is 3 times the previous number so they would be 162, 486, and 1,458.
No, it would have to be ten fourteenths to equal five sevenths or one seventh equals two fourteenths.
In a geometric sequence where the terms always increase, the common ratio ( r ) must be greater than 1. This means that each term is obtained by multiplying the previous term by this positive ratio. For example, if the first term is ( a ) and the common ratio is ( r ), the sequence would look like ( a, ar, ar^2, ar^3, \ldots ) with each term growing larger than the last. Thus, the sequence exhibits exponential growth as long as the common ratio remains above 1.
Your sequence seems to be a cubed sequence, but you are missing 64 between 27 and 125.13 = 123 = 833 = 2743 = 6453 = 12563 = 216So, next would be 73, which equals 343.