Of sorts. 1 3 6 10 15 would have a geometric representation, but would not fit the definition of a "geometric sequence".
One example of a geometric representation of the sequence would be the number of total Bowling pins as you add each row.
The first row as 1 pin, the second has 2, then 3,4,5.
1 = 1
+ 2 = 3
+ 3 = 6
+ 4 = 10
+ 5 = 15
Yes, that's what a geometric sequence is about.
A geometric sequence is : a•r^n while a quadratic sequence is a• n^2 + b•n + c So the answer is no, unless we are talking about an infinite sequence of zeros which strictly speaking is both a geometric and a quadratic sequence.
I'm guessing your sequence is 1, 3, 6, 10, 15, ... In which case it continues: 21, 28, 36, 45, 55, 66, ... (These are the triangular numbers.)
what is the recursive formula for this geometric sequence?
It is called arithmetico-geometric sequence. I have added a link with some nice information about them.
No.
Yes, that's what a geometric sequence is about.
a sequence of shifted geometric numbers
A geometric sequence is : a•r^n while a quadratic sequence is a• n^2 + b•n + c So the answer is no, unless we are talking about an infinite sequence of zeros which strictly speaking is both a geometric and a quadratic sequence.
antonette taño invented geometric sequence since 1990's
I'm guessing your sequence is 1, 3, 6, 10, 15, ... In which case it continues: 21, 28, 36, 45, 55, 66, ... (These are the triangular numbers.)
A descending geometric sequence is a sequence in which the ratio between successive terms is a positive constant which is less than 1.
what is the recursive formula for this geometric sequence?
It is called arithmetico-geometric sequence. I have added a link with some nice information about them.
No.
A geometric sequence is : a•r^n which is ascending if a is greater than 0 and r is greater than 1.
The sequence 216 12 23 is neither arithmetic nor geometric.