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When you multiply an odd number and an even number is your answer always odd?
Wiki User
∙ 13y ago
No, it's always even, and here's the proof:
All even numbers can be expressed as 2n, where n is any integer.
All odd numbers can be expressed as 2p + 1, where p is any integer.
Multiply those two together:
2n(2p + 1) = 2(2np + n). Since both 2np and n are integers, that means 2np + n is an integer; and since that integer is being multiplied by 2, it must be even.
Wiki User
∙ 13y ago
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When you multiply an odd number by an odd number is the answer always odd?
Yes - while multiplying odd numbers by even numbers will always produce an even result.
When you multiply any number of even numbers will the product always be odd?
No, the product will always be even.
What is the result of product of even numbers and odd numbers?
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
What happens when you add an odd number and an odd number?
Two odd numbers always sum to an even number. Always. Two even numbers always sum to an even number, and an odd number and an even number always sum to an odd number.
Why when you multiply an odd number with another odd number the result is a odd number?
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Why when you multiply an odd number by a even does it always equal a even?
When you multiply an odd number by an even number, you are essentially adding an even number of odd numbers together. Since adding an even number of odd numbers will always result in an even number, the product will be even.
When you multiply an odd number by an odd number is the answer always odd?
Yes - while multiplying odd numbers by even numbers will always produce an even result.
What is true about two odd numbers?
When you add them, you always get an even number; when you multiply them, the result is always odd.
What combination of numbers always results in an odd number?
Multiply two odd numbers Add an even and an odd Subtract an odd and an even
When you times by 5 the answer is always even?
if you multiply an even number by 5 then it will always end in 0 but if you multiply an odd number by 5 then it will always end in 5.
When you multiply any number of even numbers will the product always be odd?
No, the product will always be even.
If you multiply an odd number times an even number the result is?
its always an even number....im pretty sure.
What is the result of product of even numbers and odd numbers?
If you multiply one even number by one odd number, the result is always even. In general, if you multiply several numbers, and at least one of the numbers is even, the product is always even. This is because "even" means "multiple of 2", and if one of the factors contains a 2 as a factor, so will the product.
What happens when you add an odd number and an odd number?
Two odd numbers always sum to an even number. Always. Two even numbers always sum to an even number, and an odd number and an even number always sum to an odd number.
Why when you multiply an odd number with another odd number the result is a odd number?
yes, the product of 2 odd numbers is always an odd number. Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd.
Why if you multiply odd number with another number the result is always odd number?
Well, the question is why. The first number is "even" + 1. Multiply both of these by your odd number. Now the "even" times "odd" is even, because every "1" in the odd number becomes a "2". And then the remaining 1 times "odd" must be odd, which is an even +1. Add it all up and you get evens everywhere except that final "1". So the result is even + 1 which is odd. There is a quicker way if you know how to multiply bracketed terms: odd x odd = (even + 1)x(even +1)= even x even +even +even +1 = must be odd. ========================== You've just read a truly impressive answer to a question slightly different from the one that was asked. The part of the question that comes after "Why if ..." is a false statement. If you multiply odd number with another number, the result is odd number ONLY if the nother number is also odd number.
What happens if you multiply odd by even?
If you multiply an odd number by an even number, the product (answer) will be even. Example: 5 x 4 = 20
