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What else can I help you with?
What k -k equals 2?
k and -k right? -k x -1 =k k+k= 2 k= 1 unless you mean multiply then that would be -k x-1 =k k x k= 2 1.4142 rounded to the nearest ten thousandth
What is 6 more than half k?
1/2k + 6 or 0.5k + 6
Factor the expression 2 k squared minus k minus 4 equals 0?
2 k^2 - k - 4 = 0 2 (k^2 - (1/2)k - 2) = 0 2 ((k - 1/4)^2 - 1/16 - 2) = 0 2 ((k - 1/4)^2 - 33/16) = 0 2 (k - 1/4 - sqrt(33)/4)(k - 1/4 + sqrt(33)/4) = 0 32 (4k - 1 - sqrt(33))(4k - 1 + sqrt(33)) = 0
K divided by 2 - k divided by 5- k divided by6 equals 2?
k/2 -k/5 -k/6 = 2 Multply all terms by 30: 15k -6k -5k = 60 4k = 60 k = 15
20 k when k 2?
Without operational signs, I'm just guessing but if k = 2, 20 + k = 22
How do you find the two square roots of i imaginary number Answer in rectangular form?
The two square roots of i are (k, k) and (-k, -k) where k = sqrt(2)/2 = 1/sqrt(2).
K divided by 2 is 40?
To find K, you would just multiply 40 by 2 to get 80. Therefore 80/2=40.
What is the answer to this problem k squared minus 5k?
The expression ( k^2 - 5k ) can be factored as ( k(k - 5) ). To find the values of ( k ) that satisfy the equation ( k^2 - 5k = 0 ), you can set each factor to zero: ( k = 0 ) or ( k - 5 = 0 ), which gives ( k = 5 ). Thus, the solutions are ( k = 0 ) and ( k = 5 ).
What is the sum of k squared and k?
k^2 + k = k^2 + k k^2 x k = k^3
When k is added to the expression y2-12ythe expression becomes (y p)2.find the values of p and k?
To solve this problem, we need to expand the given expression (y+k)^2 and compare it to y^2 - 12y. Expanding (y+k)^2 gives y^2 + 2yk + k^2. By comparing this to y^2 - 12y, we can see that 2yk must be equal to -12y, which implies k = -6. Additionally, comparing k^2 to 0 reveals that k = 0. Therefore, the values of p and k are p = -6 and k = 0.
How do you find the formula of infinite surds?
x =√k+√k+√k…… ectx² = k + xx² - x = kx² - x + (1/2)² = k + (1/2)² factorise x² - x + (1/2)²(x + 1/2)² = k + 1/4(x + 1/2)² = (4k + 1)/4x + 1/2 = ± √(4k + 1)/2x = 1/2 ± √(4k + 1)/2it obviously has to be positivex = 1/2 + √(4k + 1)/2x = (1 + √(4k + 1))/2
Find the remainder when f of x is divided by x - k and of x equals 2x3 plus 3x2 plus 4x plus 18 and k equals -2?
To find the remainder when ( f(x) = 2x^3 + 3x^2 + 4x + 18 ) is divided by ( x - k ) where ( k = -2 ), we can use the Remainder Theorem. This states that the remainder is ( f(k) ). Calculating ( f(-2) ): [ f(-2) = 2(-2)^3 + 3(-2)^2 + 4(-2) + 18 = 2(-8) + 3(4) - 8 + 18 = -16 + 12 - 8 + 18 = 6. ] Thus, the remainder is ( 6 ).
Given y is inversely proportional to x If the difference in the values of y when x 2 and x 6 is 5 How do i find the value of y when x 4?
As y is inversely proportional to x, the equation relating x to y is given by: y = k/x where k is the constant of proportionality. Using this we can find expressions for the value of y when x = 2 and x = 6 in terms of k: x = 2 → y = k/2 x = 6 → y = k/6 The difference between these is k/2 - k/6 = 3k/6 - k/6 = 2k/6 = k/3 But this, we are told is 5; thus: k/3 = 5 → k = 15 Thus y = 15/x Now that we have found the equation relating x to y, we can plug in the value for x = 4 and find the value of y: The value for y when x = 4 is y = 15/4 = 3.75
If y varies directly as x squared find k when x 2 and y 8?
If y varies directly as x and if x = 2 when y = 8 then k = 4.
How do you find the solutions of ordered pairs?
If a line passes though (10, -3) and (2k, k) the slop of this line is 2/3. How do i find the value of k and state the new ordered pair?
What k -k equals 2?
k and -k right? -k x -1 =k k+k= 2 k= 1 unless you mean multiply then that would be -k x-1 =k k x k= 2 1.4142 rounded to the nearest ten thousandth
If y varies inversely as x and y 5 when x 2 find x when y is 4?
Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ), where ( k ) is a constant. Given that ( y = 5 ) when ( x = 2 ), we can find ( k ) by substituting these values: ( 5 = \frac{k}{2} ), which gives ( k = 10 ). Now, to find ( x ) when ( y = 4 ), we set up the equation ( 4 = \frac{10}{x} ). Solving for ( x ) gives ( x = \frac{10}{4} = 2.5 ).
