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How are the factors of polynomial P of x related to the roots of polynomial equation P of x equals to 0?
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
What are the possible values for x if x2 5x 6?
The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
How many complex roots does 6x4 plus x3 - 5 equals 0 have?
It has two complex roots.
What is the number and type of roots of the equation x2-4x-32 equals 0?
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
3x2 plus 8x plus 4 has two complex roots?
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
