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There is no sign (plus or minus) before the final 1.
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
It has two complex roots.
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
There are none because the discriminant of the given quadratic expression is less than zero.
zero
To find the roots of the polynomial (x^2 - 11x + 15), we can factor it as ((x - 5)(x - 3) = 0). Setting each factor equal to zero gives us the roots (x = 5) and (x = 3). Thus, the two values of (x) that are roots of the polynomial are (3) and (5).
The graph of a polynomial in X crosses the X-axis at x-intercepts known as the roots of the polynomial, the values of x that solve the equation.(polynomial in X) = 0 or otherwise y=0
x = -2.5 + 1.6583123951777ix = -2.5 - 1.6583123951777iwhere i is the square root of negative one.
It is difficult to tell because there is no sign (+ or -) before the 5. +5 gives complex roots and assuming that someone who asked this question has not yet come across complex numbers, I assume the polynomial is x2 -3x - 5 The roots of this equation are: -1.1926 and 4.1926 (to 4 dp)
Yes.
Yes, that is true. The real roots of a polynomial are the values of ( x ) for which the polynomial evaluates to zero, which corresponds to the points where the graph intersects the x-axis. In other words, if ( f(x) = 0 ) for some real number ( x ), then the graph of the polynomial ( f(x) ) will cross the x-axis at that point.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i