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There is no sign (plus or minus) before the final 1.
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
The equation x2+5x+6=0 simplifies to (x+2)*(x+3)=0. From this you can determine the roots by setting x+2 and x+3 equal to zero. The roots of the equation are -2 and -3.
It has two complex roots.
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
There are none because the discriminant of the given quadratic expression is less than zero.
zero
The graph of a polynomial in X crosses the X-axis at x-intercepts known as the roots of the polynomial, the values of x that solve the equation.(polynomial in X) = 0 or otherwise y=0
x = -2.5 + 1.6583123951777ix = -2.5 - 1.6583123951777iwhere i is the square root of negative one.
Yes.
It is difficult to tell because there is no sign (+ or -) before the 5. +5 gives complex roots and assuming that someone who asked this question has not yet come across complex numbers, I assume the polynomial is x2 -3x - 5 The roots of this equation are: -1.1926 and 4.1926 (to 4 dp)
The "roots" of a polynomial are the solutions of the equation polynomial = 0. That is, any value which you can replace for "x", to make the polynomial equal to zero.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
You can find the roots with the quadratic equation (a = 1, b = 3, c = -5).
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
Roots of a polynomial that can be written in the form p/q are called _____ roots. Rational ;)
A third degree polynomial could have one or three real roots.