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It is the Pythagorean Theorem, named after the creator Pythagoras. a & b are lengths of legs of a right triangle (legs are the sides adjacent the right angle. c is the length of the hypotenuse of the right triangle.
I've heard that the ancient Egyptians knew about the 3-4-5 right triangle and used that knowledge to make sure the pyramids had right angles, but I cannot find that information right now. I think I saw it on the Discovery Channel, or TLC.
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If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
If a2 plus b2 equals c2 then the triangle is?
a right triangle
How do you solve a2 plus c2 equals b2 and a equals 10 and your c is 30?
All you need to do is substitute the given values of a and c into the equation, then solve for c: a2 + c2 = b2 102 + 302 = b2 100 + 900 = b2 b2 = 1000 b = √1000 b = 10√10
If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
Why is the Pythagorean therm a2 plus b2 equals c2 not a plus b equals c?
l a2 b2 is c2!!Its completely norma
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
If a2 plus b2 equals c2 then the triangle is?
a right triangle
What are the lengths of and A plus B in a right triangle if C equals 8?
A2 + B2 = C2 If C=8, then A2 + B2 = 64
What is the algebraic formula for a2 plus b2 equals c2?
You just typed it.
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
How do you calucate a2 plus b2?
a2+2a2b+2ab2+b2
Who introduced a2 plus b2 equals c2?
Pythagoras' theorem for a right angle triangle.
How do you solve a2 plus c2 equals b2 and a equals 10 and your c is 30?
All you need to do is substitute the given values of a and c into the equation, then solve for c: a2 + c2 = b2 102 + 302 = b2 100 + 900 = b2 b2 = 1000 b = √1000 b = 10√10
If a2 plus b2 plus c2 - ab - bc - ca equals 0 then prove a equals b equals c?
a2 + b2 + c2 - ab - bc - ca = 0 => 2a2 + 2b2 + 2c2 - 2ab - 2bc - 2ca = 0 Rearranging, a2 - 2ab + b2 + b2 - 2bc + c2 + c2 - 2ca + a2 = 0 => (a2 - 2ab + b2) + (b2 - 2bc + c2) + (c2 - 2ca + a2) = 0 or (a - b)2 + (b - c)2 + (c - a)2 = 0 so a - b = 0, b - c = 0 and c - a = 0 (since each square is >=0) that is, a = b = c
