answersLogoWhite

0

The gradient of a line is designated by m, abbreviated from modulus. Modulus is an absolute value calculated by adding the squares of each part and taking the positive square root of the sum, and is derived from the Latin modus, meaning measure.

User Avatar

Wiki User

16y ago

Still curious? Ask our experts.

Chat with our AI personalities

CoachCoach
Success isn't just about winning—it's about vision, patience, and playing the long game.
Chat with Coach
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
EzraEzra
Faith is not about having all the answers, but learning to ask the right questions.
Chat with Ezra

Add your answer:

Earn +20 pts
Q: Why in maths is the gradient represented by an M?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

How do you find the gradient of a line using y equals 7x plus 2?

When the equation is given in the standard form: y = mx + c, the gradient is m. So here, y = 7x + 2 means m, the gradient, is 7.


How do you find the gradient of a Linear Equation?

If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.


What is the slope when m equals 0 and b equals 5?

The slope is normally represented by m so it is 0.


What is a gradient in maths?

The gradient of a function, in a given direction, is the change in the value of the function per unit change in the given direction. It is, thus, the rate of change of the function, with respect to the direction. It is generally found by calculating the derivative of the function along the required direction. For a straight line, it is simply the slope. That is the "Rise" divided by the "Run".


Write the standard form equation of the line passing through 4 9 and perpendicular to 2x minus 3y equals 7?

With a line in the form y = mx + c, it has gradient m and the line perpendicular to it has gradient m' such that mm' = -1, ie m' = -1/m. A line through a point (x0, y0) with gradient m' has an equation of: y - y0 = m' (x - x0) which can be rearranged to a form for y = mx + c. Thus for the line 2x - 3y = 7: 2x - 3y = 7 → 3y = 2x + 7 → y = 2/3 x + 7/3 → it has gradient 2/3 → perpendicular line has gradient -3/2 → perpendicular line through (4, 9) perpendicular to 2x - 3y = 7 has equation: y - 9 = (-3/2)(x - 4) → 2y - 18 = -3(x - 4) → 2y - 18 = -3x + 12 → 2y = 30 - 3x → 3x + 2y = 30