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With a line in the form y = mx + c, it has gradient m and the line perpendicular to it has gradient m' such that mm' = -1, ie m' = -1/m.

A line through a point (x0, y0) with gradient m' has an equation of:

y - y0 = m' (x - x0)

which can be rearranged to a form for y = mx + c.

Thus for the line 2x - 3y = 7:

2x - 3y = 7

→ 3y = 2x + 7

→ y = 2/3 x + 7/3

→ it has gradient 2/3 → perpendicular line has gradient -3/2

→ perpendicular line through (4, 9) perpendicular to 2x - 3y = 7 has equation:

y - 9 = (-3/2)(x - 4)

→ 2y - 18 = -3(x - 4)

→ 2y - 18 = -3x + 12

→ 2y = 30 - 3x

→ 3x + 2y = 30

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Q: Write the standard form equation of the line passing through 4 9 and perpendicular to 2x minus 3y equals 7?
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