With a line in the form y = mx + c, it has gradient m and the line perpendicular to it has gradient m' such that mm' = -1, ie m' = -1/m.
A line through a point (x0, y0) with gradient m' has an equation of:
y - y0 = m' (x - x0)
which can be rearranged to a form for y = mx + c.
Thus for the line 2x - 3y = 7:
2x - 3y = 7
→ 3y = 2x + 7
→ y = 2/3 x + 7/3
→ it has gradient 2/3 → perpendicular line has gradient -3/2
→ perpendicular line through (4, 9) perpendicular to 2x - 3y = 7 has equation:
y - 9 = (-3/2)(x - 4)
→ 2y - 18 = -3(x - 4)
→ 2y - 18 = -3x + 12
→ 2y = 30 - 3x
→ 3x + 2y = 30
y=-x
3x-4y-6 = 0
The slope of the perpendicular to the line passing through P1(3,6) and P2(5,1) is 2/5. Note: the slope of the original line is (change in y)/(change in x), yielding -5/2. The slope of the perpendicular is the negative reciprocal, 2/5
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The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
y=-x
There is no name for it except "A line perpendicular to a line segment and passing through its midpoint".
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
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The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the vertical line passing through (-5,-2)
y = 1/3x+4/3
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
Perpendicular lines passing through a point are at right angles to each other.
y = -(1/5)x + 9
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23