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One point in each interval. An entire interval, between two critical points, either fulfills, or doesn't fulfill, the inequality.

For example, (x-3)(x+5) > 0; the corresponding equality is (x-3)(x+5) = 0, with the two critical points x = 3 and x = -5. The intervals that must be checked are x < -5, x between -5 and 3, and x > 3.

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How is graphing a two variable inequality similar to graphing a one variable inequality?

One variable inequality- graph the point on the number line then choose a point on the point, to the left and to the right to see what gets shaded. Two variable inequality- graph the line on grid paper then choose a point on the line, to the left and to the right to see what gets shaded.


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What is the feasible region in linear programming?

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When graphing a linear inequality in two variables how do you know if the inequality represents the area above the line?

Take a sample point from either the top or bottom of the graph. I like to use (0,0) if it is not on the line. Substitute it into the inequality and if it is true then it represents all points on that line as true and vice versa.


How do you know whether to use an open circle or a closed circle when graphing an inequality and why?

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What is the process of locating the position of a point on a coordinate plane?

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A closed circle when graphing an inequality means?

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I think that you are asking about the linear inequalities with two variables, so my answer is related to them. First, you have to draw the boundary line (be careful, if your inequality does not contain the equal sign, the boundary line will be a dashed line, because the points on the line are not solutions to the inequality), which divide the coordinate system in two half-planes. Second, you have to test a point on either sides of the line (the best point is the origin, (0, 0), if it is not on the boundary line). If that point satisfies the inequality, then there are all its solutions, otherwise they are to the opposite side.


What is a boundary point in algebra?

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