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2x + y = 5 . . . thus y = 5 - 2x

x2 - y2= 3 . . . . now substitute for y in this equation.

x2 - (5 - 2x)2 = 3 . . . and after expansion this becomes,

x2 - 25 + 20x - 4x2 = 3

-3x2 + 20x - 28 = 0 . . . and this factors as,

(-3x + 14)(x - 2) = 0

Then, x = 2 , x = 14/3

When x = 2, then 2x + y = 5 gives the result y = 1.

When x = 14/3 then 2x + y = 5 gives the result y = -13/3.

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Q: What are the solutions to the simultaneous equation of 2x plus y equals 5 and x squared -y squared equals 3 showing work?
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