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How many joules of energy are needed to heat 25.0 grams of steam from 100.0 degrees Celsius to 29.25 degrees Celsius?
Wiki User
∙ 13y ago
Use this formula.
q(in Joules) = Mass * specific heat * change in temperature
I will use specific heat of water at 25 C. You can look up specific heat of steam. You say " heat to " so I assume you have final and initial heat backwards.
q = 25.0 grams H2O * 4.180 J/gC * (100.0 C - 29.25 C )
q = 7393 Joules
Wiki User
∙ 13y ago
To calculate the energy required to heat the steam, you need to use the specific heat capacity of steam, which is 2.03 J/g°C. The change in temperature is 100.0 - 29.25 = 70.75°C. The energy required can be calculated using the formula: energy = mass * specific heat capacity * temperature change. Substituting the values gives: energy = 25.0 g * 2.03 J/g°C * 70.75°C = 3608.375 J.
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What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How much energy is needed to melt g of ice at 0 Celsius?
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
How much energy is needed to increase the temperature of a kilogram of water 5 degrees?
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
How many joules are needed to change the temperature of 1 gram of water by 1C?
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
What is the amount of energy needed to increase one gram of water one degree Celsius?
The amount of energy needed to increase one gram of water by one degree Celsius is known as the specific heat capacity of water, which is 4.18 Joules/gram °C.
What is the amount of energy needed to raise the temperature of 1 gram of water by 1 degrees Celsius?
The specific heat capacity of water is 4.18 Joules/gram degrees Celsius. Therefore, it would take 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
How many joules of energy are needed to heat steam from 100 celsius to 114 celsius?
Approx 2940 Joules.
How many joules are needed to change the temperature of 100 g of water from 20 degrees Celsius to 40 degrees celsius?
8.200 J
How much energy is needed to melt g of ice at 0 Celsius?
To melt 1 gram of ice at 0°C, it requires 334 joules of energy. So for g grams of ice, the energy needed would be g multiplied by 334 joules.
How many kilojoules of energy are necessary to raise the temperature of 3 kilograms of cast iron from 30 degrees celsius to 120 degrees celsius?
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
How much heat energy is needed to convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius?
To convert 50 kg of water at 80 degrees Celsius to steam at 100 degrees Celsius, you need to calculate the heat energy needed to raise the temperature of water from 80 to 100 degrees Celsius (specific heat capacity of water) and then the heat energy needed for water to steam phase change (latent heat of vaporization of water). The total heat energy required can be calculated using the formula: Q = mcΔT + mL, where Q is the heat energy, m is the mass, c is the specific heat capacity, ΔT is the temperature change, and L is the latent heat of vaporization.
How much energy is needed to increase the temperature of a kilogram of water 5 degrees?
The specific heat capacity of water is 4.186 J/g°C. Since there are 1000 grams in a kilogram, it would require 20,930 Joules of energy to increase the temperature of a kilogram of water by 5 degrees Celsius.
How many calories are needed to raise the temp of 8.1 g of water 20 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C, which means it takes 4.18 Joules of energy to raise 1 gram of water by 1 degree Celsius. To raise the temperature of 8.1 g of water by 20 degrees Celsius, you would need 8.1 g * 20°C * 4.18 J/g°C = 676.56 Joules of energy.
How many joules are needed to change the temperature of 1 gram of water by 1C?
It takes 4.184 joules of energy to change the temperature of 1 gram of water by 1 degree Celsius.
How many calories are needed to vaporize 1 gram of boiling water at 100 degrees?
To vaporize 1 gram of boiling water at 100 degrees Celsius, it would require approximately 2260 joules, which is equivalent to about 0.54 calories. This energy is needed to break the intermolecular bonds holding water molecules together, allowing them to escape into the gas phase.
What is the amount of energy needed to raise 1 kg of a substance 1 degrees Celsius?
The amount of energy needed to raise the temperature of 1 kg of a substance by 1 degree Celsius is called the specific heat capacity of the substance. Specific heat capacity is usually measured in joules per kilogram per degree Celsius (J/kg°C). Different substances have different specific heat capacities.
What is the amount of energy needed to increase one gram of water one degree Celsius?
The amount of energy needed to increase one gram of water by one degree Celsius is known as the specific heat capacity of water, which is 4.18 Joules/gram °C.
