25% as there are four 4's in 16
It can be and is.
16/16=1. 1+16=17. 17x16=272. This uses all four 16's
Three "16"'s can go into 54, with a remainder of 6.
Let S = (16+17+18)/2 = 25.5 Then area = sqrt[S*(S-A)*(S-B)*(S-C)] where A, B and C are the three sides. =sqrt(15443.44) = 124.2716 square units.
Sulphur tom has 16 protons and its symbol is S.
I'm not sure what "16 s s and nbk" refers to. Could you please provide more context or clarify your question?
False. If s is a factor of 16, then the greatest common factor (GCF) of s and 16 would be s, not 16. The GCF is the largest number that divides both numbers evenly, and in this case, that number would be s, the smaller of the two factors.
16's 225 16's 225
S has 16 as the atomic number. It has 16 protons in a atom.
1,2,4,8 and 16
Assuming the shape is a triangle, the area is 151.65 sq in. A = √[s(s - a)(s - b)(s - c)], where s = the semi-perimeter, a, b, and c are the side lengths. Let a = 19, b = 16, c = 24, and s = (19 + 16 + 24)/2 = 29.5 So we have, A = √[s(s - a)(s - b)(s - c)] = √[29.5(29.5 - 19)(29.5 - 16)(29.5 - 24)] = 151.65 in2.
There r 16 electrons in s, sulfur. There r only 6 valence electrons
15's multiples are 1,2,4,6,3,5,7,9,10,15,20,.....................
s is the variable
16 i agree 16
25% as there are four 4's in 16