Take 3k from both sides to get k-3 equals 4, so k is 7
20
y / r2 = a constant (k) so k = 405/81 ie 5. k = y/4 when r = 2, so y = 20.
If: y = 2x+k then y^2 = 4x^2 +4kx +k^2 by squaring both sides If: x^2 +y^2 = 4 then x^2 +4x^2 +4kx +(k^2 -4) = 0 So: 5x^2 +4kx +(k^2 -4) = 0 Using the discriminant: (4k)^2 -4*5*(k^2 -4) = 0 Solving the discriminant: k = -square root of 20 or +square root of 20
1200°
k * 4 = 48 k = 48/4 k = 12 so 12 * 4 = 48
12 - 4 + k = 85 8 + k = 85 k = 77
Take 3k from both sides to get k-3 equals 4, so k is 7
50
16
neg(-k) + neg(-k) = k + k = 2k = 4
k=8k+28 k-8k=28 -7k=28 k=-(28/4) k=-4
I am assuming that k is the constant of proportionality so that f = k*a*t/b2 = 3*4*6/22 = 18
x = ¼x^4 + 4x + k where k can be any number
is multiplication , so you multiply like k(9)=36 then k would equal k=4 because you divide 9 by 36 and it equals =4
k - 32 = 16 - 2 + 4 so k - 32 = 18 and then k = 18 + 32 = 50
5k + 2 = -2 Therefore, 5k = -4 k = -4/5 k = -0.8