If: y = 2x+k then y^2 = 4x^2 +4kx +k^2 by squaring both sides
If: x^2 +y^2 = 4 then x^2 +4x^2 +4kx +(k^2 -4) = 0
So: 5x^2 +4kx +(k^2 -4) = 0
Using the discriminant: (4k)^2 -4*5*(k^2 -4) = 0
Solving the discriminant: k = -square root of 20 or +square root of 20
They are -2*sqrt(5) and +2*sqrt(5).
If: y = kx -2 is a tangent to the curve (which is not a circle) of y = x^2 -8x +7 Then: kx -2 = x^2 -8x +7 Transposing and collecting like terms: (8x+kx) -x^2 -9 = 0 Using the discriminant: (8+k)^2 -4*-1*-9 = 0 Multiplying out the brackets and collecting like terms: 16k +k^2 +28 = 0 Factorizing the above: (k+2)(k+14) = 0 meaning k = -2 or k = -14 Therefore the possible values of k are -2 or -14
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
If: y = kx -2 is a tangent to the curve (which is not a circle) of y = x^2 -8x +7 Then: kx -2 = x^2 -8x +7 Transposing and collecting like terms: (8x+kx) -x^2 -9 = 0 Using the discriminant: (8+k)^2 -4*-1*-9 = 0 Multiplying out the brackets and collecting like terms: 16k +k^2 +28 = 0 Factorizing the above: (k+2)(k+14) = 0 meaning k = -2 or k = -14 Therefore the possible values of k are -2 or -14
The possible values for k are -2 and -14 because in order for the line to be tangent to the curve the discriminant must be equal to 0 as follows:- -2x-2 = x2-8x+7 => 6-x2-9 = 0 -14x-2 = x2-8x+7 => -6-x2-9 = 0 Discriminant: 62-4*-1*-9 = 0
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
4,3,2,1,0
product
When you graph a tangent function, the asymptotes represent x values 90 and 270.
Using the discriminant the possible values of k are -9 or 9
tangent tables are used to find values of all angles..precisely..like tan 15 degress and 25 minutes.
Since there are no lists following, the answer must be "none of them!"
x (x+5) = 6 X equals 1.
A line tangent to a curve, at a point, is the closest linear approximation to how the curve is "behaving" near that point. The tangent line is used to estimate values of the curve, near that point.
1.25