If you're talking about 10 liters of water and not percent, then 10 liters. But then you'll have 60 liters of mixture. It would be 2/5 or 0.4 x 50 = 20 this would make a mix of 20/50. Waterman
5 liters
thank you
Call the unknown amount of substance R to be added a. The mixture initially contains 1 gallon of S combined with 2 gallons of R. After the addition, the mixture will contain the oiginal 1 gallon of S and (2 + a) gallons of R. In order for the content of S to be 25 % after the mixing, 1 gallon must equal 0.25(1 + 2 + a)gallons, or (1 - 0.75)gallons = (0.25)a, or a = 0.25/0.25 = 1 gallon.
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
1.9 liters.
Yes they are. An elixir is a drug dissolved in a solution that contains alcohol, and there are a bunch of them. An example is Geritol Tonic, which contains 12 percent alcohol. Nice work this should definitely clean up some drug related Q's
Just about 2 Liters.
10 liters.
There are 3 litres of alcohol in your starting mixture of 4 litres. If you add 6 litres of water you will have 3 litres of alcohol in a total of 10 litres. This is the required strength.
5.6 quarts
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
Add 0,8 L of water.
900 ounces. Since this contains 20% copper, The copper content will be 180 ounces. The original 300 ounces contain 30% copper which is also 180 ounces. Hence in the resulting mixture of 1200 ounces (300+900), the total copper is 360 ounces (180+180). Hence the copper content of resulting mixture is 360/1200 which is 30%
6 litres of 50% + 4 litres of 25%
Call the unknown amount of substance R to be added a. The mixture initially contains 1 gallon of S combined with 2 gallons of R. After the addition, the mixture will contain the oiginal 1 gallon of S and (2 + a) gallons of R. In order for the content of S to be 25 % after the mixing, 1 gallon must equal 0.25(1 + 2 + a)gallons, or (1 - 0.75)gallons = (0.25)a, or a = 0.25/0.25 = 1 gallon.
Yes. The sachet, of course, should not be eaten but should be discarded by the one who finds it. It contains only a mixture of flavourings and seasonings.
A sixtel of beer contains 19.8 liters. This is equal to 669.5 fluid ounces. A person should be able to pour 56 12-ounce glasses of beer from a sixtel.
1.76 litres
The specified volume contains 120 X 40 X 63 or 302,400 cubic centimeters. Each liter contains 1000 cubic centimeter's. Therefore, there are 302.4 liters. If the measurements are not considered exact, only two significant digits are justified, so that this should be written as 3.0 {or 3.02} X 102 liters.