3(x plus 2) expanded --> 3x+6 Check out wolframalpha.com for more explanation (not advertising)
You simply multiply the expression on the outside (in this case, 3) by each of the expressions inside the parentheses, and add everything up. In this case, 3x + 3 times 4.
3(x+4) is the same as 3x+12 when the brackets are expanded out
3x+7x+3+y= 10x+3+y
38*4 + 3 + 7 - 3x = 162 - 3x
The sum of 3x plus 2 and -4 plus 3 is 3x+1 if the equation is (3x+2)+(-4+3). If they are two separate questions, 3x+2 remains as itself while -4+3=-1.
3(x2 + 3x + 1)
9x+3
3x - 24x + 5 + 3 = -21x + 8
if 3x+7 = 3 then 3x = 3-7 3x = -4 then, x = -4/3
3x2 + 10x + 3 = (x + 3)(3x + 1).
5x+3 = 3x+11 5x-3x = 11-3 2x = 8 x = 4