x(x + 1)(x - 1)
18th December
This is 220 volts AC, I assume. 10 x 220 = 2.2kVA of power. The real power will depend on the power factor. Take the power factor times 2,200 to find the watts.
(x+1)(x-1)
(x - 1)(x + 1)(x2 + 1)
36
x(x + 1)(x - 1)
(x + 1)(x^2 - x + 1)
x(x - 1)
In an AC system power is equal to Voltage x Current x Power factor. Power factor is not constant and depends on the type of the load. Ideal value of the Power factor is 1, where as practically remains less then 1.
its equal to 1 Amps 6.25 x 10 to the 18th power
(x + 1)(x - 1)
(x2 - x + 1)(x2 + x + 1)
(x - 1)(x^2 + x + 1)
18th December
First, you can take out the common factor "x".For what remains (the factor other than "x"), you can use the formula for the difference of two cubes.
It means one billion multiplied by itself 18 times. The result of 1 billion to the 18th power, in scientific notation, is 1.0e162 or 1.0 x 10162