The answers will depend on whether you are trying to determine these for a projectile or a ballistic object, whether it is travelling in a straight line (up-down) or a trajectory and what simplifying assumptions (for example, air resistance = 0) you make.
The answers will depend on whether you are trying to determine these for a projectile or a ballistic object, whether it is travelling in a straight line (up-down) or a trajectory and what simplifying assumptions (for example, air resistance = 0) you make.
The answers will depend on whether you are trying to determine these for a projectile or a ballistic object, whether it is travelling in a straight line (up-down) or a trajectory and what simplifying assumptions (for example, air resistance = 0) you make.
The answers will depend on whether you are trying to determine these for a projectile or a ballistic object, whether it is travelling in a straight line (up-down) or a trajectory and what simplifying assumptions (for example, air resistance = 0) you make.
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The answers will depend on whether you are trying to determine these for a projectile or a ballistic object, whether it is travelling in a straight line (up-down) or a trajectory and what simplifying assumptions (for example, air resistance = 0) you make.
You can't determine velocity from that graph, because the graph tells you nothing about the direction of the motion. But you can determine the speed. The speed at any moment is the slope of a line that's tangent to the graph at that moment.
Using the Pythagorean theorem, we can determine the actual velocity in the xy plane to be (the square root of 41) m/s along the vector [5,4].
'Maximum height' means the exact point at which the velocity changes from upward to downward. At that exact point, the magnitude of the velocity is zero. It doesn't matter what the velocity was when it left your hand. That number determines the maximum height, but the velocity at that height is always zero. --------------------------------------------------------- Thus using the formula: (vf)e2 = (vi)e2+2*a*d vf = final velocity = 0 m/s vi = initial velocity = 10 m/s a = acceleration = gravity = - 9.81 m/s/s d = displacement (distance) = ? e is designating that the next figure is an exponent in the formula So the formula is: (0)e2 = (10)e2 + (2 * -9.81 * d) 0 = 100 + -19.62d adding 19.62d to both sides of the equation 19.62d = 100 dividing by 19.62 d = ~ 5.097 meters
Acceleration = (change in velocity) divided by (time for the change)
If volume can be provided then by using width, and height length can be found