If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
If that's + 10x + 21, the answer is (x + 7)(x + 3)
3
(t + 7)(2t - 3)
21 is the largest factor of 21
x2+10x+21 = (x+3)(x+7)
Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!
If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.
(x2+10x+21)/(x+3) = (x+7)
x2 + 10x + 21 = (x + 3)(x + 7)
If that's + 10x + 21, the answer is (x + 7)(x + 3)
2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3
-3x + 10x - 5 + 26 = 7x + 21
2x-3=10x+21 2x-3-2x=10x+21-2x -3=8x+21 -3-21=8x+21-21 -24=8x -3=x
The roots are -3 and -7. Easily by factoring and setting each factor equal to 0. The factors are x + 7 and x +3.
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-7 plus or minus the square root of -371) divided by 10x = -0.7 + 1.9261360284258224ix = -0.7 - 1.9261360284258224iwhere i is the square root of negative one.