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30b^(2) + 48b - 24

Factor out '6'

6(5b^(2) + 8b - 4)

Write down the factors of '5', 5 & 1. and '4' ; 4,1, + 2,2

Select a pair of factors that multiply together and then add to arrive at '8'

Hence (5 x 2) - ( 1 x 2) = 10 - 2 = 8

Open brackets

6(5b 2)(b 2)

Since the '4' is negative aamd the '8' is positive. Then the larger term is positive.

Hence 6(5b - 2)(b + 2)

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lenpollock

Lvl 17
2w ago

What else can I help you with?