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The equation for a parabola is y = 3x2 - x - 1
To find the coordinates, replace x with a number from a select range say -5 to +5 and determine the corresponding value for y.
When x = -5 : y = 75 +5 - 1 = 79
x = -4 : y = 48 + 4 - 1 = 51
x = -3 : y = 27 + 3 - 1 = 29
x = -2 : y = 12 + 2 - 1 = 13
x = -1 : y = 3 + 1 - 1 = 3
x = 0 : y = -1
x = 1 : y = 3 - 1 - 1 = 1
x = 2 : y = 12 - 2 + 1 = 11
x = 3 : y = 27 - 3 - 1 = 23
x = 4 : y = 48 - 4 - 1 = 43
x = 5 : y = 75 - 5 - 1 = 69
Plot the x, y coordinates and join the points with a smooth curve.
It is the parabola such that the coordinates of each point on it satisfies the given equation.
The answer depends on the form in which the equation of the parabola is given. For y^2 = 4ax the directrix is x = -2a.
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
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It is the parabola such that the coordinates of each point on it satisfies the given equation.
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
The answer depends on the form in which the equation of the parabola is given. For y^2 = 4ax the directrix is x = -2a.
Use the equation: (Y-k)^2 = 4a(X-h)
The given terms can't be an equation without an equality sign but a negative parabola opens down wards whereas a positive parabola opens up wards.
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
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The given equation is not that of a parabola.
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There is no answer since what is given is an expression, not an equation. The expression is that of a parabola.
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.