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There will be 4 possible solutions if all you are looking for is the angles, so you will need to find out which quadrant your angle is in.
2sin²x = sin x **Subtract sin x from both sides.
2sin²x - sin x = 0 **Then factor out sin x.
sin x(2sin x - 1) = 0 **Set each equal to zero. (AB=0 is the same as A=0 OR B=0).
sin x = 0 or 2sin x - 1 = 0 to 2sin x = 1 to sin x = 1/2
At this point all that is left to do is find out where sin x = 0 or 1/2, which is 0, 180 for sin x = 0 or 30, 150 for sin x = 1/2.
What else can I help you with?
How do you solve 2 sin squared x?
Do sin(x), square it, and then multiply it by two.
How do you proven that tan squared x-sin squared tan squared x sin squared x?
To prove the identity ( \tan^2 x - \sin^2(\tan^2 x) \sin^2 x = 0 ), we start with the definitions of tangent and sine. Recall that ( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} ). By substituting this into the equation and simplifying using the Pythagorean identity, we can show that both sides of the equation are equal. Thus, the identity holds true for all ( x ) where the functions are defined.
Is 2 sin squared x the same as 2 sin x?
No.
What is sine squared times cotangent squared times secant squared?
The answer is 1. sin^2 x cos^2/sin^2 x 1/cos^2 cos^2 will be cancelled =1 sin^2 also will be cancelled=1 1/1 = 1
How do you differentiate sin squared x plus cos squared x?
The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x
How do you solve 2 sin squared x?
Do sin(x), square it, and then multiply it by two.
What is sin squared equal to?
Sin^(2)[X] = 1 - Cos^(2)[X] It is based on Pythagorean theorem . Algebraically rearrange Sin^(2)[x] + Cos^(2)[X[ = 1^(2) = 1 Note how it looks like the Pythagorean triangle h^(2) = a^(2) + b^(2) .
What does 2sin squared theta equal and why?
It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!
How do you solve sin x multiplied to Sin squared x is equal to 1?
sin(x)*sin2(x) = 1 so sin3(x) = 1 so that sin(x) = cuberoot(1) = 1 then x = pi/2 + n*pi where n is an integer.
2 sin squared x plus sin x minus 1 is equal to 0 solve for x?
2 sin2(x) + sin(x) - 1 = 0(2 sin + 1) (sin - 1) = 0Either 2 sin(x) + 1 = 02sin(x) = -1sin(x) = -0.5x = 210°, 330°or sin(x) - 1 = 0sin(x) = 1x = 90°
What is Cos squared x equal to?
Cos^2 x = 1 - sin^2 x
What does cos squared x - Sin squared x equal?
2 x cosine squared x -1 which also equals cos (2x)
What is sine squared?
Answer 1 Put simply, sine squared is sinX x sinX. However, sine is a function, so the real question must be 'what is sinx squared' or 'what is sin squared x': 'Sin(x) squared' would be sin(x^2), i.e. the 'x' is squared before performing the function sin. 'Sin squared x' would be sin^2(x) i.e. sin squared times sin squared: sin(x) x sin(x). This can also be written as (sinx)^2 but means exactly the same. Answer 2 Sine squared is sin^2(x). If the power was placed like this sin(x)^2, then the X is what is being squared. If it's sin^2(x) it's telling you they want sin(x) times sin(x).
What does 1 - cos squared equal?
Note that an angle should always be specified - for example, 1 - cos square x. Due to the Pythagorean formula, this can be simplified as sin square x. Note that sin square x is a shortcut of (sin x) squared.
How do you solve 2 sin squared theta equals one fourth?
2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))
How do you proven that tan squared x-sin squared tan squared x sin squared x?
To prove the identity ( \tan^2 x - \sin^2(\tan^2 x) \sin^2 x = 0 ), we start with the definitions of tangent and sine. Recall that ( \tan^2 x = \frac{\sin^2 x}{\cos^2 x} ). By substituting this into the equation and simplifying using the Pythagorean identity, we can show that both sides of the equation are equal. Thus, the identity holds true for all ( x ) where the functions are defined.
What does negative sine squared plus cosine squared equal?
To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)
