0
There will be 4 possible solutions if all you are looking for is the angles, so you will need to find out which quadrant your angle is in.
2sin²x = sin x **Subtract sin x from both sides.
2sin²x - sin x = 0 **Then factor out sin x.
sin x(2sin x - 1) = 0 **Set each equal to zero. (AB=0 is the same as A=0 OR B=0).
sin x = 0 or 2sin x - 1 = 0 to 2sin x = 1 to sin x = 1/2
At this point all that is left to do is find out where sin x = 0 or 1/2, which is 0, 180 for sin x = 0 or 30, 150 for sin x = 1/2.
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Professor2Sin^2X = SinX
Divide through by 'SinX'
Hence
2SinX = 1
SinX = 1/2
X = Sin^-1(1/2)
X = 30, 150, ,210, 330, et.seq.,
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