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It is 2*sin(theta)*sin(theta) because that is how multiplication is defined!

Q: What does 2sin squared theta equal and why?

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Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.

If r-squared = theta then r = Â±sqrt(theta)

If there is a plus in between, that would be equal to 1, as a result of the Pythagorean Theorem. Otherwise, you can convert this into other forms with some of the trigonometric identities for multiplication, but you won't really get it into a simpler form.

cos2(theta) = 1 cos2(theta) + sin2(theta) = 1 so sin2(theta) = 0 cos(2*theta) = cos2(theta) - sin2(theta) = 1 - 0 = 1

2 sin^2 theta = 1/4 sin^2 theta = 1/8 sin theta = sqrt(1/8) theta = arcsin(sqrt(1/8))

Related questions

Cosine squared theta = 1 + Sine squared theta

because sin(2x) = 2sin(x)cos(x)

The derivative of (sin (theta))^.5 is (cos(theta))/(2sin(theta))

To determine what negative sine squared plus cosine squared is equal to, start with the primary trigonometric identity, which is based on the pythagorean theorem...sin2(theta) + cos2(theta) = 1... and then solve for the question...cos2(theta) = 1 - sin2(theta)2 cos2(theta) = 1 - sin2(theta) + cos2(theta)2 cos2(theta) - 1 = - sin2(theta) + cos2(theta)

(/) = theta sin 2(/) = 2sin(/)cos(/)

R^2sin(theta)d(theta)d(phi)(r-hat)

Tan^2

Your question is insufficiently precise, but I'll try to answer anyway. "Sine squared theta" usually means "the value of the sine of theta, quantity squared". "Sine theta squared" usually means "the value of the sine of the quantity theta*theta". The two are not at all the same.

If r-squared = theta then r = Â±sqrt(theta)

It is 1.

2 sin(x) + 1 = 0 2 sin(x) = -1 sin(x) = -1/2 x = 210Â° and 330Â°

Until an "equals" sign shows up somewhere in the expression, there's nothing to prove.