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Velda Stokes
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∙ 14y agoit must be put like that cuz its variables r different
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How do you the solve the equation x equals 2y in terms of x?
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
What is x-2y equals -4?
You have 2 unknowns (x,y) and only one equation, so it is unsolvable if you are trying to solve for values for x and y. However, if you are just trying to solve for x in terms of y, then the answer is x=-4+2y.
Can you solve x plus 2y equals 2?
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
How do you solve the simultanious equation 4x plus 2y equals 12 x plus 2y equals 6?
If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.
How do you find the solution to x2-4y2 equals 16 and 2y-x equals 2?
x2 - 4y2 = 16∴ (x - 2y)(x + 2y) = 162y - x = 2∴ x = 2y - 2∴ ([2y - 2] - 2y)([2y - 2] + 2y) = 16∴ (y - 1 - y)(y - 1 + y) = 16∴ -1(2y - 1) = 16∴ 1 - 2y = 16∴ -2y = 15∴ y = -7.52y - x = -2∴ -15 - x = -2∴ x = -13So the point of intersection is (-13, -7.5)
How do you the solve the equation x equals 2y in terms of x?
To solve for y in terms of x, divide both sides of the equation by 2: y = x/2.If x=2y then you have already solved for x.
Solve by the elimination method x 9y 13 -x 2y -2?
x-9y
Solve the system of equations by the methods of substitution x-2y equals 0 and 3x plus 2y equals 8?
Your answers are x = 2 & y = 1Original Equationsx - 2y = 03x + 2y = 8Solve for a variable (x)x = 2ySubstitute x with its equation3*(2y) + 2y = 86y + 2y = 88y = 8y = 1Solve for second variablex = 2*(1)x = 2Check your answer(2) - 2*(1) = 03*(2) + 2*(1) = 8
Solve x equal 2y and y equal x minus 2?
x = 2y y = x - 2 or x = 2y subtract 2y to both sides x - 2 = y subtract y and add 2 to both sides x - 2y = 0 multiply by -1 to both sides x - y = 2 -x + 2y = 0 x - y = 2 add these two equations together y = 2 substitute 2 for y into the first equation, x = 2y x = 2(2) = 4 Thus the solution of these linear system of equations is the point (4, 2). Check:
How do you solve x squared minus 2x minus 4y squared minus 4y?
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
What is x-2y equals -4?
You have 2 unknowns (x,y) and only one equation, so it is unsolvable if you are trying to solve for values for x and y. However, if you are just trying to solve for x in terms of y, then the answer is x=-4+2y.
How do you solve x squared minus 4 y squared?
x^(2) - 4y^(2) Before calculating , we note #1 ' There is a negative sign between the two squares. So it will factor #2 ' '4' is the square of '2' . So we can redraw the terms as ( 2y)^2 Hence x^(2) - (2y)^2) This now satisfies the two conditions above. . So it will factor to ( x - 2y)(x + 2y) Note the different signs in each bracket . You hve asked for it to be solved!!! To solve you need to equate the terms to a value. In this case use '0' Hence (x - 2y)(x + 2y) = 0 Taking each bracket in turn x - 2y = 0 x = 2y or 2 = x/y or y = x/2 Then x + 2y = 0 x = -2y or -2/x/y or y = x/-2 Are the possible forms of solution. NB If you have two squared terms and a positive (+) between them, then it does NOT factor. NNB Think of the Pythagorean Equation a^2 + b^2 = h^2 This DOES NOT factor. However a^2 = h^2 - b^2 (Algebraic rearrangement) , DOES factor to a^2 = (h - b)(h + b)
How do you solve 6x plus 2y equals 4?
6x+2y=4 gives y=2-(1/3)x
How do you solve the system of equation x plus 2y-2 3x plus 4y6?
If you mean x+2y = -2 and 3x+4y = 6 then the solutions to the equations are x = 10 and y = -6
Can you solve x plus 2y equals 2?
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
How do you solve each system by substitution or addition 2y-x equals 3 and x equals 3y-5?
Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?
How do you solve the simultanious equation 4x plus 2y equals 12 x plus 2y equals 6?
If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.
