For example: L - Length & W - Width
start
sum = 0
input L, W
sum = L * W
print "The area of the rectangle is: SUM"
end
Remember that the area of a rectangle is width * height: static int getArea(Rectangle r) { return r.width * r.height; }
start read pie area circum print area print circum stop
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Perform encryption on the following PT using RSA and find the CT p = 3; q = 11; M = 5
By using that one thing.
to find area and perimeter of a rectangle
That's correct!
Write an algorithm to find the root of quadratic equation
40
Remember that the area of a rectangle is width * height: static int getArea(Rectangle r) { return r.width * r.height; }
The area of rectangle is : 896.0
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
maybe
find the perimeter and area of a rectangle that is 15cm long and 5cm wide
in order to find area of rectangle=(len*bred)
start read pie area circum print area print circum stop