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I think what you want is rise/run which is 10/1

sorry, not very helpful, but I'm not quite sure what you're asking

Q: How do you write an equation in slope-form with a slope of 5 and a y-intercept of -3?

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you say undefined

Any vertical line has an undefined slope. The equation of the vertical line is x = a where the x-intercept is a.

Y=mc+b

If you have any expression that defines a line, you can find the slope of the line. After you have found the slope of the line, you can then write an expression describing the line in slope intercept form. You can't define a slope-intercept form for any nonlinear equation, because the slope is always* changing; there are often several intercepts as well.

y=-2x+3

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You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)

The equation of a line with an undefined slope is x = a.

you say undefined

-12

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

Any vertical line has an undefined slope. The equation of the vertical line is x = a where the x-intercept is a.

y= slope + y-intercept

-1

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.

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