4
false
shut up and do your hw
Suppose that you have simple two variable model: Y=b0+b1X1+e The least squares estimator for the slope coefficient, b1 can be obtained with b1=cov(X1,Y)/var(X1) the intercept term can be calculated from the means of X1 and Y b0=mean(Y)-b1*mean(X1) In a larger model, Y=b0+b1X1+b2X2+e the estimator for b1 can be found with b1=(cov(X1,Y)var(X2)-cov(X2,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) to find b2, simply swap the X1 and X2 terms in the above to get b2=(cov(X2,Y)var(X1)-cov(X1,Y)cov(X1,X2))/(var(X1)var(X2)-cov(X1,X2)2) Find the intercept with b0=mean(Y)-b1*mean(X1)-b2*mean(X2) Beyond two regressors, it just gets ugly.
This question can only be answered if the probability distribution functions of X1, X2 and X3 are known. They are not and so the question cannot be answered.
it equals x1 it equals x1
4
false
3
2x2+7/x1
formula for the midpoint of a line
It is false-apex
The 2013 BMW X1 has 16 valves.
The 2014 BMW X1 has 16 valves.
GIven 2 distance points (x1,y1) and (x2,y2) we can draw a line between those point and the midpoint formula finds the midpoint of that line. Call the midpoint (m1,m2) then it is [ (x1+x1 )/2 , (y1+y2/2)]
The answer is: X1 = 2 X2 = -7
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4