Q: How much sand is needed for a 8 ft by 6 ft a depth of 18 inches?

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192

32 cubic ft.

630 cubic inches

Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.

.21 yards of sand will fill an area 115 inches by 67 inches to a depth of 2.5 inches.

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192

32 cubic ft.

630 cubic inches

It will take 72 sq. ft. of sand. Or 2.66 sq. yds. That will fill the box even.

72 cubic feet

Volume of sand required = 7 ft * 7 ft * 1/6 ft = 49/6 cubic feet = 8.166... cubic ft.

4 inches deep would be the minium coverage of sand needed for a horse area

use a known volume container to measure a quantity = 200 x (the depth you want the sand).

.21 yards of sand will fill an area 115 inches by 67 inches to a depth of 2.5 inches.

4 x 6 x .75 = 18 cu ft of sand

You convert everything to compatible units. Then you multiply area x depth. I suggest you convert the depth to feet; in that case, the answer will be in cubic feet.

You need 4.27 cubic feet. Weight in pounds is deceptive for sand depending on how wet or dry the sand is.