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The same way you'd factor any other similar equation. You're going to run into the complication that the roots of that equation are not real numbers, though; unless you know what complex numbers are, you won't be able to do it.

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10y ago
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11y ago

Yes. There is an easy solution for the difference of two squares, but the sum of two squares is a different matter.

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14y ago

x2 + 4x + 4 = (x+2)2

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9y ago

(x + 2)(x + 2)

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9y ago

That factors to 4(x^2 + 4)

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14y ago

4x + 16 = 4 (x + 4)

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9y ago

4(x + 4)

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Q: How to Factor x squared plus 4x plus 4?
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