4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
x - 4x + 4 = -3x + 4 which cannot be factorised.
4
4x2+13x+3 m*n=(4*3)=12 m+n=13 m=12 n=1 (4x/12)=(x/3) (4x+1)(x+3)
4(x^2 + x + 3)
4(x+y)^2
(2x+3)(2x+4)
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
The derivative of 2x2 + 4x + 8 is 4x+4.
x(x-4)
x2 + 4x = x(x+4)
x2 + 4x = x(x + 4)
It is: 4x(1+4)
4x^(2) - 8x '4' is common to both '4' & '8' . So tak outr '4'. Hence 4(x^(2) - 2x) Inside the brackets 'x' is common to both 'x^(2) & '2x'. So take out 'x'. Hence 4x(x - 2) Done , fully factored.
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
3x2 + 4x factors to x(3x + 4)