4x2+13x+3
m*n=(4*3)=12
m+n=13
m=12
n=1
(4x/12)=(x/3)
(4x+1)(x+3)
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5(4x - 3)(2x + 5)
12x2+13x-35 = (4x-5)(3x+7) 12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15 (12x + 28)(12x - 15) now simplify by 4 and 3 (3x + 7)(4x - 5)
13x^3
(x + 3)(4x + 5)
Take out the common factor, 3: 3x + 6 = 3(x + 2).