4x2+13x+3
m*n=(4*3)=12
m+n=13
m=12
n=1
(4x/12)=(x/3)
(4x+1)(x+3)
5(4x - 3)(2x + 5)
12x2+13x-35 = (4x-5)(3x+7) 12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15 (12x + 28)(12x - 15) now simplify by 4 and 3 (3x + 7)(4x - 5)
13x^3
(x + 3)(4x + 5)
Take out the common factor, 3: 3x + 6 = 3(x + 2).
(4x2 - 13x - 12)/(4x+ 3) = (4x + 3)(x - 4)/(4x + 3) = (4x + 3)(x - 4)/(4x + 3) = x - 4 :)
7x-5+2x=3-4x+12 7x+2x-5=3+12-4x 9x-5=15-4x 9x+4x-5=15-4x+4x 13x-5=15 13x-5+5=15+5 13x=20 13x/13=20/13 x=20/13
4x + 3 doesn't factor. It is in its simplest form.
2x2+13x+15 = (2x+3)(x+5)
(4x + 3)(4x + 3) (4x + 3)2
(3x + 2)(2x + 3)
(4x - 3)(4x - 1)
(x + 10)(x + 3)
(x - 10)(x - 3)
4(x^2 + x + 3)
x2 + 4x + 3 =(x + 3) (x + 1)
It is: 4(x+3)