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Richard Grimes
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How do you turn 5 x squared y into 10x y squared?
multiply by 2y/x
What is y when x is one third and the formula is y equals -x squared?
Y = - (1/3)2y = - 1/9
What is y cubed minus two y squared plus 4 y?
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
Factorise xy plus 5yz-2y?
if you take a factor of (Y) you end up with Y(X+5Z-2).
What is 2y squared minus 9y minus 5 factored?
(2y+1)(y−5)
What does y x y eqeal?
Y squared (Y^2)
What is 2y squared times y cubed?
2y squared * y cubed= 2y^5 (2y to the fifth power)
Factorise y 2 - 2y?
0
Subtract 4y cubed plus 2y squared plus y from 5y cubed - y?
9y cubed plus 2y squared
How do you factorise y squared minus 10y plus 16?
(y - 8)(y - 2)
How do you factorise 9 minus y squared?
1st of all, if you mean 9-y2 its simply a difference between two squares formula (3-y) (3+y)
What is the sum of 2y plus 1 and y squared plus 1?
(2y + 1) + (y^2 + 1) = 2y + 1 + y^2 + 1 = y^2 + 2y + 2
How do you turn 5 x squared y into 10x y squared?
multiply by 2y/x
What is y when x is one third and the formula is y equals -x squared?
Y = - (1/3)2y = - 1/9
What is y cubed minus two y squared plus 4 y?
y^(3) - 2y^(2) + 4y Factor out 'y' Hence y(y^2 - 2y + 4) This will not factor any further.
What are the solutions to the simultaneous equations of x equals 2y -2 and x squared equals y squared plus 7 showing work and answers?
If: x = 2y-2 and x^2 = y^2+7 Then: (2y-2)^2 = y^2+7 So: (2y-2)(2y-2) = y^2+7 It follows: 4y^2-y^2-8y+4-7 = 0 => 3y^2-8y-3 = 0 Solving the above quadratic equation: y = -1/3 or y = 3 Solutions: when y = 3 then x = 4 and when y = -1/3 then x = -8/3
Factorise xy plus 5yz-2y?
if you take a factor of (Y) you end up with Y(X+5Z-2).
