Yes.
U
if b + a , since a+b equals b + a due to it being commutative . it shud have the same magnitude and direction
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The magnitude of C cannot be >20.
The vectors can not be both equal, but they can have the same magnitude of 3, if they are at a 60 degree angle.
Any non-zero number y along with B/y will do.
if b + a , since a+b equals b + a due to it being commutative . it shud have the same magnitude and direction
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The magnitude of C cannot be >20.
The vectors can not be both equal, but they can have the same magnitude of 3, if they are at a 60 degree angle.
Any non-zero number y along with B/y will do.
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
20-4X5=0 so to make it zero it should be multiplied by 0 hence B=0
When b is zero.
Any number multiplied by zero is zero. (10b also means 10 times zero.)
The Y-Axis intercept, i.e. when X is zero, Y is b.
Either a=0 or b=0
The magnitude is the same, the direction vector is not.