Yes.
if b + a , since a+b equals b + a due to it being commutative . it shud have the same magnitude and direction
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The magnitude of C cannot be >20.
The vectors can not be both equal, but they can have the same magnitude of 3, if they are at a 60 degree angle.
Any non-zero number y along with B/y will do.
if b + a , since a+b equals b + a due to it being commutative . it shud have the same magnitude and direction
Scalar product = (magnitude of 'A') times (magnitude of 'B') times (cosine of the angle between 'A' and 'B')
The magnitude of C cannot be >20.
The vectors can not be both equal, but they can have the same magnitude of 3, if they are at a 60 degree angle.
Any non-zero number y along with B/y will do.
Any number to the power '0' equals '1'. Proof ; Let a^(n) = b Then dividing a^(n) / a^(n) = b/b a^(n-n) = b/b a^(0) = 1
B could be either greater than, lesser than or equal to A. 7 +(-7) = 0 (-7) = 7 = 0 0 + 0 = 0
20-4X5=0 so to make it zero it should be multiplied by 0 hence B=0
When b is zero.
Any number multiplied by zero is zero. (10b also means 10 times zero.)
If A + B = 0, this means that vector A is equal in magnitude but opposite in direction to vector B. In other words, the two vectors are anti-parallel to each other. This relationship indicates that the components of the two vectors cancel each other out when added together, resulting in a net vector of zero.
Either a=0 or b=0