3
To determine if ( x^3 ) is a solution of the equation ( 3x - 54x = 0 ), we first simplify the equation. The left side simplifies to ( -51x = 0 ), which implies ( x = 0 ) is the only solution. Since ( x^3 ) is not equal to ( 0 ) for any ( x ) other than ( 0 ), ( x^3 ) is not a solution to the equation.
3=x+3-5x subtract 3 from both sides 0=x-5x combine 0=-4x 0=x
4x2 - x - 3 = 0 (x - 1)(4x + 3) = 0 So x - 1 = 0 or 4x + 3 = 0 ie x = 1 or = -3/4 = -0.75
2x2 - x - 15 = 0(2x + 5) (x - 3) = 0[2x + 5 = 0] and [x - 3 = 0]x = -5/2 and x = 3{-2.5, 3}
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
Only if O x=3
To determine if ( x^3 ) is a solution of the equation ( 3x - 54x = 0 ), we first simplify the equation. The left side simplifies to ( -51x = 0 ), which implies ( x = 0 ) is the only solution. Since ( x^3 ) is not equal to ( 0 ) for any ( x ) other than ( 0 ), ( x^3 ) is not a solution to the equation.
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
3=x+3-5x subtract 3 from both sides 0=x-5x combine 0=-4x 0=x
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
4x2 - x - 3 = 0 (x - 1)(4x + 3) = 0 So x - 1 = 0 or 4x + 3 = 0 ie x = 1 or = -3/4 = -0.75
2x2 - x - 15 = 0(2x + 5) (x - 3) = 0[2x + 5 = 0] and [x - 3 = 0]x = -5/2 and x = 3{-2.5, 3}
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3