If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
Using the quadratic formula, I found the solution set is x=2,x=-9
divide by 3. (x+2) (x-2) = 0 set both equal to 0 x= -2 and x= 2
x2-5x = 24 x2-5x-24 = 0 (x-8)(x+3) = 0 x = 8 or x -3
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x2 - 4x = 0 x(x - 4) = 0 so either x = 0 or x - 4 = 0 that is, x = 0 or x = 4.
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
0
x^2 - 4x -12 = 0 (x + 2) (x - 6) = 0 x + 2 = 0 or x - 6 = 0 x + 2 - 2 = 0 -2 or x - 6 + 6 = 0 + 6 x = -2 or x = 6
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
x=x+1 0=1 this is impossible so there is no solution.
x2 + 6x = 16x2 + 6x - 16 = 0(x + 8)(x - 2) = 0x + 8 = 0 or x - 2 = 0x = -8 or x = 2Since it is given that x > 0, then x = -8 is not a solution of the equation. Thus, the only solution is x = 2.
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
Actually, you wouldn't be able to solve that problem. 0/x would equal 0 but x/0 does not have a solution. The common phrase in this is "undefined."