If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
Using the quadratic formula, I found the solution set is x=2,x=-9
divide by 3. (x+2) (x-2) = 0 set both equal to 0 x= -2 and x= 2
x2-5x = 24 x2-5x-24 = 0 (x-8)(x+3) = 0 x = 8 or x -3
Yes, for example: | x | = 0 with the only solution: x = 0
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
x = 0 or x = 2
Yes.
x2 - 4x = 0 x(x - 4) = 0 so either x = 0 or x - 4 = 0 that is, x = 0 or x = 4.
If you have -2x = 0, to solve for x, divide each side by two. That results in x = -0/2, or x = 0. So there is only one solution.
Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.
(x-6)(x+4) = 0 x = 6 or x = -4
3