Only if O x=3
If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
Using the quadratic formula, I found the solution set is x=2,x=-9
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
divide by 3. (x+2) (x-2) = 0 set both equal to 0 x= -2 and x= 2
x/4 - 4 = x/4 4x/4 - 4 x 4 = x x - 16 = x 0 = 16 There is no solution to the equation.
Yes, for example: | x | = 0 with the only solution: x = 0
x-2y=0 x=2y The solution set is the set of all (x,y) such that x=2y
To determine if ( x^3 ) is a solution of the equation ( 3x - 54x = 0 ), we first simplify the equation. The left side simplifies to ( -51x = 0 ), which implies ( x = 0 ) is the only solution. Since ( x^3 ) is not equal to ( 0 ) for any ( x ) other than ( 0 ), ( x^3 ) is not a solution to the equation.
x - 9 = 0 x - 9 = 0 x - 9 = 0 x - 9 = 0
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
x = 0 or x = 2
Yes.
x2 - 4x = 0 x(x - 4) = 0 so either x = 0 or x - 4 = 0 that is, x = 0 or x = 4.
If you have -2x = 0, to solve for x, divide each side by two. That results in x = -0/2, or x = 0. So there is only one solution.
The inequality ( x - 1837 ) is incomplete as it lacks a relational operator (like <, >, ≤, or ≥). If you meant to solve ( x - 1837 > 0 ), then the solution would be ( x > 1837 ). If you meant ( x - 1837 < 0 ), the solution would be ( x < 1837 ). Please provide the complete inequality for a specific solution.
Yes, 0, 2 is a solution to y=-x+2 because 0=-2+2 which can be rewritten as 2-2=0.
Here is an example: x + 5 = 5If you subtract five from both sides, you get x = 0, which is an example of getting 0 as a solution for an equation.