Only if O x=3
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If you mean: y+x = 3 then the solutions are (0, 3) and (3, 0)
Using the quadratic formula, I found the solution set is x=2,x=-9
x = 00 reduces to x = 0/0. Both are undefined, and thus cannot be considered "equal". Other than that, nothing.
divide by 3. (x+2) (x-2) = 0 set both equal to 0 x= -2 and x= 2
x/4 - 4 = x/4 4x/4 - 4 x 4 = x x - 16 = x 0 = 16 There is no solution to the equation.