A number is divisible by 6 if it is divisible both by 2 and 3 1240 is even then is divisible by 2 1+2+4+0 = 7 which is not divisible by 3 then 1240 is not divisible by 3 Thus 1240 is not divisible by 6
Not completely sure what that number is. I'm guessing 10,534,341 which is divisible by 3.
3 is not divisible by 72. 72 is divisible by 3.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
34 is divisible by 2 seventeen times. 34 is divisible by 3 eleven times with one left over.
To determine which number is divisible by 3, 6, and 9, we need to check if the sum of the digits of each number is divisible by 3. For 369: 3+6+9 = 18, which is divisible by 3, 6, and 9. Therefore, 369 is divisible by 3, 6, and 9. For 246: 2+4+6 = 12, which is divisible by 3 but not by 6 or 9. Therefore, 246 is divisible by 3 but not by 6 or 9. For 468: 4+6+8 = 18, which is divisible by 3, 6, and 9. Therefore, 468 is divisible by 3, 6, and 9. For 429: 4+2+9 = 15, which is divisible by 3 but not by 6 or 9. Therefore, 429 is divisible by 3 but not by 6 or 9. Therefore, the numbers 369 and 468 are divisible by 3, 6, and 9.
468 is divisible by all of its factors, 1, 2, 3, 4, 6, 9, 12, 13, 18, 26, 36, 39, 52, 78, 117, 156, 234, and 468.
yes the answear is 156 :)
104 792 468 976 552
The prime factorization of 468 = 2 * 2 * 3 * 3 * 13 This can also be written using exponents as: 22 * 32 * 13
No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
18000
Unfortunately, the least common multiple in this case is rather large. 468 is the smallest number that is divisible by both 13 and 36. 36 is already divisible by 3 so 3 does not matter for this problem. 13 is prime and is not a factor of 36 so the first multiple of 13 that is divisible by 36 is 13 * 36 which is 468.
2 x 2 x 3 x 3 x 13 = 468
468/2=234 234/2=117 117/3=39 39/3=13 2x2x3x3x13
123 is not divisible by 2 it is divisible by 3
416 is divisible by 2 but is not divisible by 3.